document.write( "Question 515993: Mr. Jackson is 13 years less than three times as old as his son. Six years ago he was fourteen years more than twice as old as his son was then. Find each of their ages today \n" ); document.write( "
Algebra.Com's Answer #344918 by Maths68(1474)\"\" \"About 
You can put this solution on YOUR website!
Let
\n" ); document.write( "Present age of Mr. Jackson = j
\n" ); document.write( "Present age of Son = s\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Mr. Jackson is 13 years less than three times as old as his son.
\n" ); document.write( "j=3s-13........(1)
\n" ); document.write( "Six years ago he was fourteen years more than twice as old as his son was then.
\n" ); document.write( "j-6=2(s-6)+14
\n" ); document.write( "j-6=2s-12+14
\n" ); document.write( "j-6=2s+2
\n" ); document.write( "j=2s+2+6
\n" ); document.write( "j=2s+8..............(2)
\n" ); document.write( "Put the value of j from (1) to (2)
\n" ); document.write( "3s-13=2s+8
\n" ); document.write( "3s-2s=8+13
\n" ); document.write( "s=21
\n" ); document.write( "Put the value of s in (1)
\n" ); document.write( "j=3s-13........(1)
\n" ); document.write( "j=3(21)-13
\n" ); document.write( "j=63-13
\n" ); document.write( "j=50\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Present age of Mr. Jackson = j = 50 years old
\n" ); document.write( "Present age of Son = s = 21 years old
\n" ); document.write( " \n" ); document.write( "
\n" );