document.write( "Question 517673: 8 years ago a dad was 8 times older than his son.\r
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document.write( "Today their combined ages are 52, how old are they today? \n" );
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Algebra.Com's Answer #344914 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Dad = d \n" ); document.write( "Present age of Son = s\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Today their combined ages are 52 \n" ); document.write( "d+s=52 \n" ); document.write( "d=52-s.........(1) \n" ); document.write( "8 years ago a dad was 8 times older than his son. \n" ); document.write( "d-8=8(s-8) \n" ); document.write( "d-8=8s-64 \n" ); document.write( "d=8s-64+8 \n" ); document.write( "d=8s-56.......(2) \n" ); document.write( "Put the value of d from (1) to (2) \n" ); document.write( "52-s=8s-56 \n" ); document.write( "-s-8s=-56-52 \n" ); document.write( "-9s=-108 \n" ); document.write( "-9s/-9=-108/-9 \n" ); document.write( "s=12 \n" ); document.write( "Put the value of s in (1) \n" ); document.write( "d=52-12 \n" ); document.write( "d=40\r \n" ); document.write( "\n" ); document.write( "Present age of Dad = d = 40 years old \n" ); document.write( "Present age of Son = s = 12 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |