document.write( "Question 517758: The width of a rectangle is three digits shorter than its length. The area is 180 square digits. find the length and width\r
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\n" ); document.write( "\n" ); document.write( "x sqared -3x-180=0\r
\n" ); document.write( "\n" ); document.write( "what do I do next
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Algebra.Com's Answer #344913 by deborabr(181)\"\" \"About 
You can put this solution on YOUR website!
x^2-3x-180=0
\n" ); document.write( "(-3)^2-4(1)(-180)
\n" ); document.write( "9+720=729 -> delta
\n" ); document.write( "x=[-(-3)+/- root 729]/2*1
\n" ); document.write( "x=[3 +/- 27]/2
\n" ); document.write( "x'= [3+27]/2 x'=30/2 x'=15
\n" ); document.write( "x\"= [3-27]/2 x\"=-24/2 x\"=-12
\n" ); document.write( " answer x'=15 and x\"=-12\r
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