document.write( "Question 517758: The width of a rectangle is three digits shorter than its length. The area is 180 square digits. find the length and width\r
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document.write( "This is what I have so far....\r
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document.write( "x sqared -3x-180=0\r
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document.write( "what do I do next \n" );
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Algebra.Com's Answer #344913 by deborabr(181)![]() ![]() You can put this solution on YOUR website! x^2-3x-180=0 \n" ); document.write( "(-3)^2-4(1)(-180) \n" ); document.write( "9+720=729 -> delta \n" ); document.write( "x=[-(-3)+/- root 729]/2*1 \n" ); document.write( "x=[3 +/- 27]/2 \n" ); document.write( "x'= [3+27]/2 x'=30/2 x'=15 \n" ); document.write( "x\"= [3-27]/2 x\"=-24/2 x\"=-12 \n" ); document.write( " answer x'=15 and x\"=-12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |