document.write( "Question 517745: Please help this is all one problem and I am struggling with it.\r
\n" ); document.write( "\n" ); document.write( "Write a function rule for the area of a rectangle with a length of 2 ft less than three times its width. What is the area of the rectangle when its width is 2 ft?
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Algebra.Com's Answer #344891 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Start with the formula for the area of a rectangle:
\n" ); document.write( "\"A+=+L%2AW\"
\n" ); document.write( "But the length, L, is given as:
\n" ); document.write( "\"L+=+3W-2\" \"...length is 2ft. less than three times its width.\" Substitute this into the area formula.
\n" ); document.write( "\"A+=+%283W-2%29%2AW\" Simplify.
\n" ); document.write( "\"highlight%28A+=+3W%5E2-2W%29\" This is the function you need.
\n" ); document.write( "When the width is 2ft., then W = 2, so substitute.
\n" ); document.write( "\"A+=+3%282%29%5E2-2%282%29\"
\n" ); document.write( "\"A+=+12-4\"
\n" ); document.write( "\"A+=+8\"
\n" ); document.write( "So when the width is 2ft., the area is 8sq.ft.
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