document.write( "Question 517717: In a river with a steady current, it takes the bionic women 6 minutes to swim a certain distance upstream, but it takes her only 3 minutes to swim back. How many minutes would it take a doll of the bionic women to float this same distance downstream. \n" ); document.write( "
Algebra.Com's Answer #344881 by ankor@dixie-net.com(22740)\"\" \"About 
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In a river with a steady current, it takes the bionic women 6 minutes to swim a certain distance upstream, but it takes her only 3 minutes to swim back.
\n" ); document.write( " How many minutes would it take a doll of the bionic women to float this same distance downstream.
\n" ); document.write( ":
\n" ); document.write( "It may be easier to just assume a distance: 240 meters
\n" ); document.write( "then
\n" ); document.write( "\"240%2F6\" = 40 m/min speed upstream
\n" ); document.write( "and
\n" ); document.write( "\"240%2F3\" = 80 m/min speed downstream
\n" ); document.write( ":
\n" ); document.write( "Let s = speed in still water
\n" ); document.write( "Let c = speed of the current, the dolls speed,
\n" ); document.write( ":
\n" ); document.write( "s - c = 40
\n" ); document.write( "s + c = 80
\n" ); document.write( "-----------adding eliminates c, find s
\n" ); document.write( "2s = 120
\n" ); document.write( "s = 60 m/min in still water
\n" ); document.write( "find c
\n" ); document.write( "60+c = 80
\n" ); document.write( "c = 80 - 60
\n" ); document.write( "c = 20 m/min speed of the current
\n" ); document.write( ":
\n" ); document.write( "Find the time for doll to drift 240 m at 20 m/min
\n" ); document.write( "\"240%2F20\" = 12 min for the doll to float the same distance.
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