document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=517605>Question 517605</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line through (1,1) perpendicular to line y=2x+10 please. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344860 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write an equation of the line through (1,1) perpendicular to line y=2x+10<BR>\n" );
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document.write( "Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept<BR>\n" );
document.write( "For given equation: y=2x+10<BR>\n" );
document.write( "slope=2<BR>\n" );
document.write( "slope of line perpendicular to given equation=-1/2 (negative reciprocal of slope of given equation)<BR>\n" );
document.write( "Equation of line thru (1,1):<BR>\n" );
document.write( "y=-x/2+b<BR>\n" );
document.write( "solving for b using coordinates of given point (1,1)<BR>\n" );
document.write( "1=-1/2+b<BR>\n" );
document.write( "b=1+1/2=3/2<BR>\n" );
document.write( "equation of perpendicular line: y=-x/2+3/2 </SPAN>\n" );
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