document.write( "Question 517110: if the ratio of two brothers' ages is 3 : 2
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document.write( "and their total age is 60 years old, what is the difference in their ages? \n" );
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Algebra.Com's Answer #344856 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "One Brother's age = x \n" ); document.write( "Other Brother's age = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ratio of two brothers' ages is 3 : 2 \n" ); document.write( "x:y=3:2 \n" ); document.write( "x/y=3/2 \n" ); document.write( "x=3y/2..........(1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Their total age is 60 years old \n" ); document.write( "x+y=60 \n" ); document.write( "Put the value of x in above equation \n" ); document.write( "3y/2+y=60 \n" ); document.write( "Multiply by 2 both sides \n" ); document.write( "3y+2y=60*2 \n" ); document.write( "5y=120 \n" ); document.write( "5y/5=120/5 \n" ); document.write( "y=24 \n" ); document.write( "Put the value of y in (1) \n" ); document.write( "x=3y/2 \n" ); document.write( "x=3(24)/2 \n" ); document.write( "x=3*12 \n" ); document.write( "x=36\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "One Brother's age = 36 \n" ); document.write( "Other Brother's age = 24 \n" ); document.write( "Difference between their ages = 36-24=12\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "36:24=3:2 \n" ); document.write( "36/24=3/2 \n" ); document.write( "3/2=3/2 \n" ); document.write( " |