document.write( "Question 517110: if the ratio of two brothers' ages is 3 : 2
\n" ); document.write( "and their total age is 60 years old, what is the difference in their ages?
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Algebra.Com's Answer #344856 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "One Brother's age = x
\n" ); document.write( "Other Brother's age = y\r
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\n" ); document.write( "\n" ); document.write( "The ratio of two brothers' ages is 3 : 2
\n" ); document.write( "x:y=3:2
\n" ); document.write( "x/y=3/2
\n" ); document.write( "x=3y/2..........(1)\r
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\n" ); document.write( "\n" ); document.write( "Their total age is 60 years old
\n" ); document.write( "x+y=60
\n" ); document.write( "Put the value of x in above equation
\n" ); document.write( "3y/2+y=60
\n" ); document.write( "Multiply by 2 both sides
\n" ); document.write( "3y+2y=60*2
\n" ); document.write( "5y=120
\n" ); document.write( "5y/5=120/5
\n" ); document.write( "y=24
\n" ); document.write( "Put the value of y in (1)
\n" ); document.write( "x=3y/2
\n" ); document.write( "x=3(24)/2
\n" ); document.write( "x=3*12
\n" ); document.write( "x=36\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "One Brother's age = 36
\n" ); document.write( "Other Brother's age = 24
\n" ); document.write( "Difference between their ages = 36-24=12\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "36:24=3:2
\n" ); document.write( "36/24=3/2
\n" ); document.write( "3/2=3/2
\n" ); document.write( "
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