document.write( "Question 517111: if twice berthas age is increased by 4 less than 3 times her age the result is 71 equation \n" ); document.write( "
Algebra.Com's Answer #344855 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Bertha = b\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Twice Bertha's age = 2b \n" ); document.write( "Three times of Bertha's age = 3b\r \n" ); document.write( "\n" ); document.write( "if twice berthas age is increased by 4 less than 3 times her age the result is 71 \n" ); document.write( "(2b+4)-3b=71 \n" ); document.write( " |