document.write( "Question 517243: In 3 years Darla will be twice as old as she was 8 years ago. How old is Darla today? \n" ); document.write( "
Algebra.Com's Answer #344851 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Darla = d\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Her age in three years = d+3 \n" ); document.write( "Her age 8 years ago = d-8\r \n" ); document.write( "\n" ); document.write( "In 3 years Darla will be twice as old as she was 8 years ago. \r \n" ); document.write( "\n" ); document.write( "d+3=2(d-8) \n" ); document.write( "d+3=2d-16 \n" ); document.write( "d-2d=-16-3 \n" ); document.write( "-d=-19 \n" ); document.write( "Multiply by -1 both sides \n" ); document.write( "d=19\r \n" ); document.write( "\n" ); document.write( "Darla is 19 years old Now!!! \n" ); document.write( " |