document.write( "Question 51694: How can I find the square root of 456 using the trial divisor method \n" ); document.write( "
Algebra.Com's Answer #34485 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! How can I find the square root of 456 using the \r\n" ); document.write( "trial divisor method?\r\n" ); document.write( "\r\n" ); document.write( "-------------------------------------------------\r\n" ); document.write( "\r\n" ); document.write( "Write 456 as 456.000000. Then group it into pairs\r\n" ); document.write( "of digits, right and left of the decimal, Consider\r\n" ); document.write( "the introductory 4 to be the pair of digits 04. Each\r\n" ); document.write( "SINGLE digit of the answer will be placed over a PAIR\r\n" ); document.write( "of digits.\r\n" ); document.write( " . \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " \r\n" ); document.write( "The largest digit that does not exceed the square root\r\n" ); document.write( "of the digit pair 04 is 2, so write 2 above the pair of \r\n" ); document.write( "digits 04. \r\n" ); document.write( "\r\n" ); document.write( " 2 \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( "\r\n" ); document.write( "Square 2, getting 04. Write it below the pair of digits 04\r\n" ); document.write( "Draw a line under it\r\n" ); document.write( "\r\n" ); document.write( " 2 . \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 04\r\n" ); document.write( " ---\r\n" ); document.write( "\r\n" ); document.write( "Subtract getting 00 then bring down the next pair of digits\r\n" ); document.write( "56. Draw a vertical line to the left of 00 56\r\n" ); document.write( "\r\n" ); document.write( " 2 . \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 04\r\n" ); document.write( " ---\r\n" ); document.write( " |00 56\r\n" ); document.write( " \r\n" ); document.write( "So far we have 2 in the answer. Multiply 2 by 20. (Double it\r\n" ); document.write( "and annex a 0). This gives 40. Write the 40 to the left of\r\n" ); document.write( "the vertical line:\r\n" ); document.write( "\r\n" ); document.write( " 2 . \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( "\r\n" ); document.write( "40 is the TRIAL divisor. Divide 40 into \"00 56\" (interpreted as\r\n" ); document.write( "just 56). It goes 1+ times, so write 1 as the next digit in the \r\n" ); document.write( "answer.\r\n" ); document.write( "\r\n" ); document.write( " 2 1. \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " \r\n" ); document.write( "Now to get the ACTUAL divisor, add the 1 to the the trial divisor,\r\n" ); document.write( "getting 41, and write this actual divisor under the 40 and place\r\n" ); document.write( "another vertical line to the right of it.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2 1. \r\n" ); document.write( " ---------------\r\n" ); document.write( " | 4 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41| \r\n" ); document.write( " \r\n" ); document.write( "Multiply the 1 times the ACTUAL divisor, getting 41. Write it\r\n" ); document.write( "as \"00 41\" and write it beside the vertical line at the bottom\r\n" ); document.write( "underneath the 00 56. Draw a line underneath and subtract, getting\r\n" ); document.write( "15. Then bring down the next pair of digits 00. Then draw a \r\n" ); document.write( "vertical line to the left of the 15. \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2 1. \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41|00 41\r\n" ); document.write( " -----\r\n" ); document.write( " |15 00\r\n" ); document.write( " \r\n" ); document.write( "The digits in the answer so far are 21. So multiply this by 20\r\n" ); document.write( "(Double 21, getting 42, then annex a 0 to get 420). Write 420\r\n" ); document.write( "left of the vertical line. 420 is the next TRIAL divisor. \r\n" ); document.write( "\r\n" ); document.write( " 2 1. \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41| 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Divide the TRIAL divisor 420 into \"15 00\" (interpreted as\r\n" ); document.write( "1500). It goes 3+ times, so write 3 as the next digit in the \r\n" ); document.write( "answer.\r\n" ); document.write( "\r\n" ); document.write( " 2 1. 3 \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41| 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now to get the next ACTUAL divisor, add the 3 to the the trial divisor,\r\n" ); document.write( "getting 423, and write this actual divisor under the 420 and place\r\n" ); document.write( "another vertical line to the right of it.\r\n" ); document.write( "\r\n" ); document.write( " 2 1. 3 \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41|00 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( " 423| \r\n" ); document.write( " \r\n" ); document.write( "Now multiply the 3 times the ACTUAL divisor, 423, getting 1296, and\r\n" ); document.write( "write it as \"12 96\" underneath the \"15 00\" and subtract, getting 231.\r\n" ); document.write( "So write this as \"02 31\", and draw a vertical line left of it \r\n" ); document.write( "\r\n" ); document.write( " 2 1. 3 \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41|00 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( " 423| 12 69\r\n" ); document.write( " -------\r\n" ); document.write( " |02 31 \r\n" ); document.write( "\r\n" ); document.write( "The digits in the answer so far are 213. So multiply this by 20\r\n" ); document.write( "(Double 213, getting 426, then annex a 0 to get 4260). Write 4260\r\n" ); document.write( "left of the vertical line. 4260 is the next TRIAL divisor. \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2 1. 3 \r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41|00 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( " 423| 12 69\r\n" ); document.write( " -------\r\n" ); document.write( " 4260|02 31 00\r\n" ); document.write( " 4265|\r\n" ); document.write( "\r\n" ); document.write( "Continue this process as long as you like. Here is the\r\n" ); document.write( "finished problem taken to the nearest thousandth:\r\n" ); document.write( "\r\n" ); document.write( " 2 1. 3 5 4\r\n" ); document.write( " ---------------\r\n" ); document.write( " |04 56. 00 00 00\r\n" ); document.write( " 4\r\n" ); document.write( " ---\r\n" ); document.write( " 40|00 56\r\n" ); document.write( " 41|00 41\r\n" ); document.write( " -----\r\n" ); document.write( " 420| 15 00\r\n" ); document.write( " 423| 12 69\r\n" ); document.write( " -------\r\n" ); document.write( " 4260|02 31 00\r\n" ); document.write( " 4265|02 13 25\r\n" ); document.write( " ---------\r\n" ); document.write( " 42700|17 75 00\r\n" ); document.write( " 42704|17 08 16\r\n" ); document.write( " --------\r\n" ); document.write( " 66 84\r\n" ); document.write( "\r\n" ); document.write( "To get another decimal place annex another \"00\" pair\r\n" ); document.write( "to bring down.\r\n" ); document.write( "\r\n" ); document.write( "Why does it work? I won't show the whole thing. But\r\n" ); document.write( "here's an idea to get you started if you are interested. \r\n" ); document.write( "\r\n" ); document.write( "(10u + t)² = 100u² + 20tu + t\r\n" ); document.write( "\r\n" ); document.write( "Notice that 20u is the coefficient of t in the second term.\r\n" ); document.write( "That is related to why we multiply u by 20 to get the TRIAL \r\n" ); document.write( "divisor 20tu. The t on the end is related to why we must \r\n" ); document.write( "add the t to get the ACTUAL divisor. \r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |