document.write( "Question 517385: Jason is 21 years older than his sister Sarah. In 5 years he will be twice as old as Sarah. How old is each of them now? \n" ); document.write( "
Algebra.Com's Answer #344849 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! Let \n" ); document.write( "Present age of Jason = j \n" ); document.write( "Present age of Sarah = s\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jason is 21 years older than his sister Sarah. \n" ); document.write( "j=s+21.............(1) \n" ); document.write( "In 5 years their age will be \n" ); document.write( "j+5=s+5 \n" ); document.write( "then he will be twice as old as Sarah. \n" ); document.write( "j+5=2(s+5) \n" ); document.write( "j+5=2s+10 \n" ); document.write( "j=2s+10-5 \n" ); document.write( "j=2s+5..............(2) \n" ); document.write( "Put the value of j from (1) to (2) \n" ); document.write( "s+21=2s+5 \n" ); document.write( "s-2s=5-21 \n" ); document.write( "-s=-16 \n" ); document.write( "Multiply by -1 both sides \n" ); document.write( "s=16 \n" ); document.write( "Put the value of s in (1) \n" ); document.write( "j=s+21 \n" ); document.write( "j=16+21 \n" ); document.write( "j=37 \n" ); document.write( "Present age of Jason = j = 37 years old \n" ); document.write( "Present age of Sarah = s = 16 years old \n" ); document.write( " \n" ); document.write( " |