document.write( "Question 517495: How do u make 3 over (x+7) and 4 over (x-8) have common denominators the problem is. 3/(x+7) + 4/(x-8) \n" ); document.write( "

Algebra.Com's Answer #344803 by oberobic(2304) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+3%2F%28x%2B7%29+%2B+4%2F%28x-8%29+\"$
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\n" ); document.write( "First consider the equivalent form:
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\n" ); document.write( " $\"+a%2Fb+%2B+c%2Fd+=+%28ad%2Bbc%29%2Fbd+\"$
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\n" ); document.write( "Then substitute.
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\n" ); document.write( " $\"+a+=+3+\"$
\n" ); document.write( " $\"+b+=+%28x%2B7%29+\"$
\n" ); document.write( " $\"+c+=+4+\"$
\n" ); document.write( " $\"+d+=+%28x-8%29+\"$
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