document.write( "Question 517434: Five years ago, Allen was two years older than 5/6 of his age today. What is his age today? \n" ); document.write( "
Algebra.Com's Answer #344797 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let a = his age today \n" ); document.write( "then \n" ); document.write( "(a-5) = his age 5 yrs ago \n" ); document.write( ": \n" ); document.write( "Write an equation for what it says: \n" ); document.write( ": \n" ); document.write( "\"Five years ago, Allen was two years older than 5/6 of his age today.\" \n" ); document.write( "a - 5 = \n" ); document.write( "Multiply both sides by 6, get rid of the fraction, results \n" ); document.write( "6(a-5) = 5a + 12 \n" ); document.write( "6a - 30 = 5a + 12 \n" ); document.write( "6a - 5a = 12 + 30 \n" ); document.write( "a = 42 yrs, his age today \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that works in the statement \n" ); document.write( "\"Five years ago, Allen was two years older than 5/6 of his age today. \" \n" ); document.write( "42 - 5 = \n" ); document.write( "37 = 35 + 2 \n" ); document.write( " |