document.write( "Question 517291: With the major options package and destination charge, a sports car costs 24,416. The base price of the car was 10 times the price of the major options package and fifty times the destination charge. What was the base price of the car? \n" ); document.write( "
Algebra.Com's Answer #344796 by MathTherapy(10557)\"\" \"About 
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test/517291: With the major options package and destination charge, a sports car costs 24,416. The base price of the car was 10 times the price of the major options package and fifty times the destination charge. What was the base price of the car?
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\n" ); document.write( "\n" ); document.write( "Let sports package be S, destination charge, D, and base price, B
\n" ); document.write( "Then S = B/10
\n" ); document.write( "Also, D = B/50\r
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\n" ); document.write( "\n" ); document.write( "Now, since S + D + B = 24,416, then we can say that:\r
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\n" ); document.write( "\n" ); document.write( "B/10 + B/50 + B = 24,416 ----- Substituting values for S & D
\n" ); document.write( "5B + B + 50B = 1,220,800 ------- Multiplying by LCD, 50
\n" ); document.write( "56B = 1,220,800\r
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\n" ); document.write( "\n" ); document.write( "B, or base price of car = \"%281220800%29%2F56\", or $\"highlight_green%2821800%29\"\r
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\n" ); document.write( "\n" ); document.write( "D, or destination charge = $\"21800%2F50\" or $436\r
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\n" ); document.write( "\n" ); document.write( "S, or sports package = $\"21800%2F10\", or $2,180\r
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\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "$21,800 + 436 + 2,180 = $24,416\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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