document.write( "Question 517417: ann and nancy use a metal alloy that is 16% copper to make jewerly. How many ounces of a 11% alloy must be mixed with a 24% allot to form 130 ounces of the desired alloy? \n" ); document.write( "
Algebra.Com's Answer #344774 by josmiceli(19441)\"\" \"About 
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Let \"a\" = ounces of 11% alloy needed
\n" ); document.write( "Let \"b\" = ounces of 24% alloy needed
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+a+%2B+b+=+130+\"
\n" ); document.write( "(2) \"+%28+.11a+%2B+.24b+%29+%2F+130+=+.16+\"
\n" ); document.write( "-----------------------------
\n" ); document.write( "(2) \"+.11a+%2B+.24b+=+.16%2A130+\"
\n" ); document.write( "(2) \"+.11a+%2B+.24b+=+20.8+\"
\n" ); document.write( "(2) \"+11a+%2B+24b+=+2080+\"
\n" ); document.write( "Multiply both sides of (1) by \"+11+\"
\n" ); document.write( "and subtract (1) from (2)
\n" ); document.write( "(2) \"+11a+%2B+24b+=+2080+\"
\n" ); document.write( "(1) \"+-11a+-+11b+=+-1430+\"
\n" ); document.write( "\"+13b+=+650+\"
\n" ); document.write( "\"+b+=+50+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+130+\"
\n" ); document.write( "(1) \"+a+=+130+-+50+\"
\n" ); document.write( "(1) \"+a+=+80+\"
\n" ); document.write( "80 ounces of 11% alloy are needed
\n" ); document.write( "50 ounces of 24% alloy are needed
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+%28+.11%2A80+%2B+.24%2A50+%29+%2F+130+=+.16+\"
\n" ); document.write( "(2) \"+%28+8.8+%2B+12+%29+%2F+130+=+.16+\"
\n" ); document.write( "(2) \"+20.8+=+.16%2A130+\"
\n" ); document.write( "(2) \"+20.8+=+20.8+\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );