document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51682>Question 51682</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534405991/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I have the answer in the back of the book. Still having trouble getting there.\r<BR>\n" );
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document.write( "4^2/3 * 6^2/3 * 9^2/3\r<BR>\n" );
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document.write( "Have tried squaring 4 and then taking the cubed root but don't get good numbers.\r<BR>\n" );
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document.write( "The book says answer is 36????? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34477 by </B><A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><B>mathchemprofessor(65)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4^2/3 * 6^2/3 * 9^2/3=(4^2)^(1/3)*(6^2)^(1/3)*(9^2)^(1/3)<BR>\n" );
document.write( "=(16)^(1/3)*(36)^(1/3)*(81)^(1/3)<BR>\n" );
document.write( "-(16*36*81)^(1/3)=(46656)^(1/3)=(36^3)^(1/3)=36<BR>\n" );
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