document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51685>Question 51685</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, the measure of the first angle is twice the measure of the second angle. The measure of the third angle is 8degrees less than the measure of the second angle. What is the measure of each angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34476 by </B><A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><B>mathchemprofessor(65)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathchemprofessor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34476\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the measure of the second angle be x degrees. Since the measure of the first angle is twice that of the second one, the first angle is 2x.<BR>\n" );
document.write( "Given that, the third angle is 8 degrees less than the second one, it should be (x-8) degrees.<BR>\n" );
document.write( "Sum of the angles in a triangle=180 degrees<BR>\n" );
document.write( "So,2x+x+(x-8)=180<BR>\n" );
document.write( "4x-8=180<BR>\n" );
document.write( "4x=180+8=188<BR>\n" );
document.write( "Dividing both sides by 4, we get<BR>\n" );
document.write( "x=47 <BR>\n" );
document.write( "So, the first angle is 2*47=94 degrees<BR>\n" );
document.write( "Second angle=47 degrees<BR>\n" );
document.write( "Third angle=47-8=39 degrees. </SPAN>\n" );
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