document.write( "Question 517404: at 10 am a car leaves a house at a rate of 60 mi/h. At the same time, another car leaves the same house at a rate of 50 mi/h in the opposite direction. At what time will the cars be 333 miles apart? \n" ); document.write( "

Algebra.Com's Answer #344759 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can think of this as one car standing still
\n" ); document.write( "and the other moving at the sum of their speeds.
\n" ); document.write( "I'll say the 50 mi/hr car is standing still.
\n" ); document.write( " $\"+d+=+r%2At\"$
\n" ); document.write( " $\"+333+=+%28+60+%2B+50+%29%2At+\"$
\n" ); document.write( " $\"+333+=+110t+\"$
\n" ); document.write( " $\"+t+=+333%2F110+\"$
\n" ); document.write( " $\"+t+=+3.0273+\"$ hrs
\n" ); document.write( "10 AM + 3hrs = 1 PM
\n" ); document.write( " $\"+.0273%2A60+=+1.636+\"$
\n" ); document.write( " $\"+.636%2A60+=+38+\"$
\n" ); document.write( "They will be 333 mi apart at 1:01:38 PM \n" ); document.write( "

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