document.write( "Question 51672: isbn-0618372628\r
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Algebra.Com's Answer #34467 by rchill(405)\"\" \"About 
You can put this solution on YOUR website!
Expand the equation to \"5-3n=4%2B3n\". Now add 3n to both sides to get \"5=4%2B6n\". Subtract 4 from both sides yields \"1=6n\". Now divide both sides by 6 to get \"1%2F6=n\". \n" ); document.write( "
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