document.write( "Question 517086: victor has 16.25 in coin if there were twice as many 5 centavo coins as 25 centavo coin and as many 10 centavo coin as 5 centavo coin and 25 centavo coin combine how many coin of each type were there? \n" ); document.write( "
Algebra.Com's Answer #344660 by JBarnum(2146)\"\" \"About 
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\"%28x-3%29%2F5=6\" multiply both sides by 5
\n" ); document.write( "\"x-3=30\" add 3 to both sides
\n" ); document.write( "\"x=33\"
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