document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=517004>Question 517004</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find three consecutive even integers, such that the sum of the second and third number is 20 more than the first. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344592 by </B><A HREF=/tutors/aboutme.mpl?userid=jessica43><B>jessica43(140)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jessica43><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344592\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To solve this equation you need to write equations using what you know.  First, you know that the numbers are 3 consecutive even integers.  So A is your first, B = A + 2 and C = B + 2.<BR>\n" );
document.write( "Next, you know that the sum of the second and third numbers is 20 more than the first: B + C = 20 + A.<BR>\n" );
document.write( "Now plug the first two equations into the second, for B and C:<BR>\n" );
document.write( "B + C = 20 + A<BR>\n" );
document.write( "(A + 2) + (B + 2) = 20 + A<BR>\n" );
document.write( "A + 2 + B + 2 = 20 + A<BR>\n" );
document.write( "A + B + 4 = 20 + A<BR>\n" );
document.write( "B + 4 = 20<BR>\n" );
document.write( "B = 16<BR>\n" );
document.write( "So the three consecutive even numbers are 14, 16, 18. </SPAN>\n" );
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