document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516951>Question 516951</A>: <I><SPAN STYLE=\"word-break: break-all;\"> THE RATIO OF THE MEASURE OF A SUPPLEMENT OF AN ANGLE TO THE MEASURE OF A COMPLEMENT IS 4:1. Find the measure of the angle, the complement, and the supplement. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344566 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let angle be x<BR>\n" );
document.write( "supplement = 180-x<BR>\n" );
document.write( "complement = 90-x\r<BR>\n" );
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document.write( "(180-x)/(90-x)=4/1\r<BR>\n" );
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document.write( "cross multiply<BR>\n" );
document.write( "180-x=4(90-x)<BR>\n" );
document.write( "180-x =360-4x<BR>\n" );
document.write( "3x=180<BR>\n" );
document.write( "x=60 deg </SPAN>\n" );
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