document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516947>Question 516947</A>: <I><SPAN STYLE=\"word-break: break-all;\"> When Ricky was 10 years old, his father was 45. How many years must pass for Ricky to be 5 years older than one-fifth as old as his father? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344559 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344559\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the number of years be x\r<BR>\n" );
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document.write( "Ricky's age after x years = x+10\r<BR>\n" );
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document.write( "Father's age after 5 years = x+45\r<BR>\n" );
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document.write( "x+10= 1/5(x+45)+5\r<BR>\n" );
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document.write( "multiply equation by 5\r<BR>\n" );
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document.write( "5(x+10)=(x+45)+25<BR>\n" );
document.write( "5x+50=x+45+25<BR>\n" );
document.write( "5x-x=25-50+45<BR>\n" );
document.write( "4x=20<BR>\n" );
document.write( "x=5  years<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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