document.write( "Question 516859: -7x+3y=52
\n" ); document.write( "15x+6y=-12\r
\n" ); document.write( "\n" ); document.write( "Please help! I am supposed to solve this by substitution, and I have no idea how to do it!
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Algebra.Com's Answer #344525 by Maths68(1474)\"\" \"About 
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-7x+3y=52................(1)
\n" ); document.write( "15x+6y=-12..............(2)\r
\n" ); document.write( "\n" ); document.write( "Take (1)
\n" ); document.write( "-7x+3y=52................(1)
\n" ); document.write( "3y=52+7x
\n" ); document.write( "3y/3=(52+7x)/3
\n" ); document.write( "y=(52+7x)/3
\n" ); document.write( "Put the above value of y in (2)
\n" ); document.write( "15x+6y=-12
\n" ); document.write( "15x+6((52+7x)/3)=-12
\n" ); document.write( "15x+2((52+7x)=-12
\n" ); document.write( "15x+104+14x=-12
\n" ); document.write( "29x=-12-104
\n" ); document.write( "29x=-116
\n" ); document.write( "29x/29=-116/29
\n" ); document.write( "x=-116/29
\n" ); document.write( "Put the value of x in (1)
\n" ); document.write( "-7x+3y=52................(1)
\n" ); document.write( "-7(-116/29)+3y=52
\n" ); document.write( "(812/29)+3y=52
\n" ); document.write( "3y=52-(812/29)
\n" ); document.write( "3y=(1508-812)/29
\n" ); document.write( "3y=696/29
\n" ); document.write( "3y=24
\n" ); document.write( "3y/3=24/3
\n" ); document.write( "y=8\r
\n" ); document.write( "\n" ); document.write( "x,y = -116/29, 8\r
\n" ); document.write( "\n" ); document.write( "Check \r
\n" ); document.write( "\n" ); document.write( "put the values of x and y in (1)
\n" ); document.write( "-7x+3y=52................(1)
\n" ); document.write( "-7(-116/29)+3(8)=52
\n" ); document.write( "812/29+24=52
\n" ); document.write( "(812+696)/29=52
\n" ); document.write( "1508/29=52
\n" ); document.write( "1508=52*29
\n" ); document.write( "1508=1508
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