document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516897>Question 516897</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to you determine the volume and surface area of a box that is 10 inches high, 3 inches wide, and 4 inches deep? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344524 by </B><A HREF=/tutors/aboutme.mpl?userid=gc2000><B>gc2000(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gc2000><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gc2000><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344524\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> volume: THREE dimensional: length x heigth x width(or \"deep\", it doesn't matter what you call it, as long as there are three dimensions): 10 x 3 x 4 = 120 inches cubed, or \"cubic inches\".\r<BR>\n" );
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document.write( "surface area: TWO dimensional: add up each face of the box: that is, the area of each of the six sides. two opposite sides are 3 x 4 = 12; two are 3 x 10 = 30, two are 4 x 10 = 40: <BR>\n" );
document.write( "add them up, <BR>\n" );
document.write( "2*12 + 2*30 + 2*40 <BR>\n" );
document.write( "24 + 60 + 80<BR>\n" );
document.write( "= 164<BR>\n" );
document.write( "Surface area of the exterior sides of the box = 164 in. squared, or \"square inches\" </SPAN>\n" );
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