document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516803>Question 516803</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve<BR>\n" );
document.write( "2x -5y -3z =7<BR>\n" );
document.write( "-4x +10y + 2z = 6<BR>\n" );
document.write( "6x -15y - z = -19 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344522 by </B><A HREF=/tutors/aboutme.mpl?userid=gc2000><B>gc2000(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gc2000><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gc2000><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Sorry, this can't be solved to arrive at a unique solution for x and y, although z = -5.\r<BR>\n" );
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document.write( "These equations do not have one unique solution because in each of the three equations x and y are expressed in the exact same ratio (2x : -5y); therefore many (actually infinite) x and y \"answers\" that fit with that ratio can \"successfully\" be substituted into all three equations. The z terms have different ratios in relation to x and y, and therefore z can be solved via substitution and/or adding equations; resulting in z = -5; but since there is no proper solution, I didn't show work.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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