document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516807>Question 516807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Peggy invested $1000, part at 8% per annum and the remainder at 9% per annum.  After one year, her total interest from these investments was $84.  How much did she invest at each rate?\r<BR>\n" );
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document.write( "How would you solve this question? What would the let statements be? Can you please guide me through the process. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344509 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344509\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the amount Peggy invested at 8% per annum, then the remainder ($1000-x) was invested at 9% per annum. The total interest earned on these two amounts is given as $84.00<BR>\n" );
document.write( "We can express the interest earned on the two amounts as:<BR>\n" );
document.write( "0.08x as the interest earned on amount x at 8% and 0.09(1000-x) as the amount earned on the remainder at 9%.  The sum of these two amounts is given as $84.00 so this can be expressed in the equation:<BR>\n" );
document.write( "0.08x+0.09(1000-x) = 84 Simplify and solve for x.<BR>\n" );
document.write( "0.08x+90-0.09x = 84<BR>\n" );
document.write( "-0.01x+90 = 84 Subtract 90 from both sides.<BR>\n" );
document.write( "-0.01x = -6 Divide by -0.01<BR>\n" );
document.write( "x = 600 and 1000-x = 400<BR>\n" );
document.write( "Peggy invested $600 at 8% per annum and $400 at 9% per annum. </SPAN>\n" );
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