document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516754>Question 516754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is one fourth its length. the perimeter is 60 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344480 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344480\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = 2(L+W) =60<BR>\n" );
document.write( ".<BR>\n" );
document.write( "W = 1/4*L<BR>\n" );
document.write( ".<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2(L+W) = 60<BR>\n" );
document.write( "2L +2(1/4*L) = 60<BR>\n" );
document.write( "2L + 1/2L = 60<BR>\n" );
document.write( ".<BR>\n" );
document.write( "multiply by 2 to cancel the fraction<BR>\n" );
document.write( ".<BR>\n" );
document.write( "4L + L = 120<BR>\n" );
document.write( "5L = 24<BR>\n" );
document.write( ".<BR>\n" );
document.write( "W = 1/4*24 = 6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "check the perimeter<BR>\n" );
document.write( "P = 2(24+6) = 2(30) = 60<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Answer:  Length = 24, Width = 6<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Done. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );