document.write( "Question 516685: We are using the standard normal random variable is between 0 and Z table\r
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document.write( "I need to find the probability for
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document.write( "mean of 22 feet height and standard deviation is 4 feet
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document.write( "A. what is the probability that the height is greater than 17
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document.write( "B. height is less than 13 feet
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document.write( "C. the height is between 25 and 31 feet\r
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document.write( "I tried x-u/O to get z score and looked up in the table and all my answers have been wrong please help me understand how to find probability\r
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document.write( "Thank You
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document.write( "Beverly \n" );
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Algebra.Com's Answer #344450 by stanbon(75887) ![]() You can put this solution on YOUR website! mean of 22 feet height and standard deviation is 4 feet \n" ); document.write( "A. what is the probability that the height is greater than 17 \n" ); document.write( "z(17) = (17-22)/4 = -5/4 \n" ); document.write( "P(x > 17) = P(z > -5/4) = 0.8944 \n" ); document.write( "----------------------------------- \n" ); document.write( "B. height is less than 13 feet \n" ); document.write( "z(13) = (13-22)/4 = -9/4 \n" ); document.write( "P(x < 13) = P(z < -9/4) = 0.122 \n" ); document.write( "------------------------------- \n" ); document.write( "C. the height is between 25 and 31 feet \n" ); document.write( "--- \n" ); document.write( "Find the z value of 25 and of 31. \n" ); document.write( "The find the probability that z is between those two values. \n" ); document.write( "Ans: 0.2144 \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " \n" ); document.write( " |