document.write( "Question 516433: A 40% solution of sulfuric acid is created by diluting a 25ml solution of 88% sulfuric acid with water. How much water must be added to the 25ml 88% solution to obtain the 40% sulfuric acid solution? \n" ); document.write( "
Algebra.Com's Answer #344367 by nerdybill(7384)\"\" \"About 
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A 40% solution of sulfuric acid is created by diluting a 25ml solution of 88% sulfuric acid with water. How much water must be added to the 25ml 88% solution to obtain the 40% sulfuric acid solution?
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\n" ); document.write( "Let x = amount (ml) of water added
\n" ); document.write( "then
\n" ); document.write( ".88(25) = .40(25+x)
\n" ); document.write( "22 = 10 + .40x
\n" ); document.write( "12 = .40x
\n" ); document.write( "30 ml = x
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