document.write( "Question 516389: For each function, find f(-2), f(-1/2), f(3), and f(7).
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document.write( "1. f(x)= -1/3x + 1 \n" );
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Algebra.Com's Answer #344355 by Maths68(1474)![]() ![]() You can put this solution on YOUR website! For each function, find f(-2), f(-1/2), f(3), and f(7).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)= -1/3x + 1 \n" ); document.write( "f(-2)=-1/3(-2)+1 \n" ); document.write( "f(-2)=1/6+1 \n" ); document.write( "f(-2)=(1+6)/6 \n" ); document.write( "f(-2)=7/6\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)= -1/3x + 1 \n" ); document.write( "f(-1/2)=-1/(3(1/-2))+1 \n" ); document.write( "f(-1/2)=-1/(3/-2)+1 \n" ); document.write( "f(-1/2)=2/3+1 \n" ); document.write( "f(-1/2)=(2+3)/3 \n" ); document.write( "f(-1/2)=5/3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)= -1/3x + 1 \n" ); document.write( "f(3)=-1/3(3)+1 \n" ); document.write( "f(3)=-1/9+1 \n" ); document.write( "f(3)=(-1+9)/9 \n" ); document.write( "f(3)=8/9\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "f(x)= -1/3x + 1 \n" ); document.write( "f(7)=-1/3(7)+1 \n" ); document.write( "f(7)=-1/21+1 \n" ); document.write( "f(7)=(-1+21)/21 \n" ); document.write( "f(7)=20/21 \n" ); document.write( " \n" ); document.write( " |