document.write( "Question 516387: A metallurgist has one alloy containing 25% copper and another containing 62% copper. How many pounds of each alloy must he use to make 45 pounds of a third alloy containing 34% copper? \n" ); document.write( "
Algebra.Com's Answer #344353 by Maths68(1474)\"\" \"About 
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Ally A
\n" ); document.write( "Amount = x
\n" ); document.write( "Concentration = 25%=0.25
\n" ); document.write( "================================================================================
\n" ); document.write( "Alloy B
\n" ); document.write( "Amount = 45-x pounds
\n" ); document.write( "Concentration = 62%=0.62
\n" ); document.write( "================================================================================
\n" ); document.write( "Resultant Alloy
\n" ); document.write( "Amount=45
\n" ); document.write( "Concentration=34%=0.34
\n" ); document.write( "================================================================================
\n" ); document.write( "(Amount of A * Concentration of A)+(Amount of B * Concentration of B) = (Amount of Resultant * Concentration of Resultant)
\n" ); document.write( "(x*0.25)+(45-x)(0.62)=(45)*0.34
\n" ); document.write( "0.25x+27.9-0.62x=15.3
\n" ); document.write( "-0.37x=15.3-27.9
\n" ); document.write( "-0.37x=-12.6
\n" ); document.write( "-0.37x/-0.37=-12.6/-0.37
\n" ); document.write( "x=34.05 pounds
\n" ); document.write( "============================
\n" ); document.write( "Ally A
\n" ); document.write( "Amount = 34.04 pounds
\n" ); document.write( "Concentration = 25%=0.25
\n" ); document.write( "================================================================================
\n" ); document.write( "Alloy B
\n" ); document.write( "Amount = 45-x=45-34.04=10.95 pounds
\n" ); document.write( "Concentration = 62%=0.62\r
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