document.write( "Question 516357: a chemist has a 10 ml of a 30% acid solution. how many millilters of pure acid must be added to obtain a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #344351 by Maths68(1474) $\"\"$ $\"About$

You can put this solution on YOUR website!
Soluton A
\n" ); document.write( "Amount = 10 ml
\n" ); document.write( "Concentration = 30%=0.3
\n" ); document.write( "================================================================================
\n" ); document.write( "Solution B
\n" ); document.write( "Amount = x ml
\n" ); document.write( "Concentration = 100%=1 (Pure acid)
\n" ); document.write( "================================================================================
\n" ); document.write( "Resultant Solution
\n" ); document.write( "Amount=10+x ml
\n" ); document.write( "Concentration=50%=0.5
\n" ); document.write( "================================================================================
\n" ); document.write( "(Amount of A * Concentration of A)+(Amount of B * Concentration of B) = (Amount of Resultant * Concentration of Resultant)
\n" ); document.write( "(10*0.3)+(x*1)=(10+x)*0.50
\n" ); document.write( "3+x=5+0.5x
\n" ); document.write( "x-0.5x=5-3
\n" ); document.write( "0.5x=2
\n" ); document.write( "0.5x/0.5=2/0.5
\n" ); document.write( "x=4 ml
\n" ); document.write( "================================================================================
\n" ); document.write( "10 ml of a 30% acid solution and 4 ml of pure acid must be mixed to obtain 14 ml of 50% solution \n" ); document.write( "

\n" );