document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516377>Question 516377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Not sure how to find the slope of the line joining (3, 12) and (15, -2)as a fraction in the simplest form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344350 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3, 12) and (15, -2)<BR>\n" );
document.write( "Slope of line = Change in y /  change in x<BR>\n" );
document.write( "m=y2-y1/x2-x1<BR>\n" );
document.write( "m=-2-12/15-3<BR>\n" );
document.write( "m=-14/12<BR>\n" );
document.write( "m=-7/6\r<BR>\n" );
document.write( "\n" );
document.write( "Slope = -7/6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );