document.write( "Question 516363: write an equation in slope-intercept form for a line that passes through the given point and is parallel to the given line
\n" ); document.write( "y=5x;(2,-1)
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Algebra.Com's Answer #344349 by Maths68(1474)\"\" \"About 
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Standard Form of Equation of the line:
\n" ); document.write( "y=mx+b
\n" ); document.write( "Given line
\n" ); document.write( "y=5x
\n" ); document.write( "Compare above equation with the standard form equation
\n" ); document.write( "Slope = m=5 and y-intercept = b=0
\n" ); document.write( "Since parallel lines have same slope so slope of the required line will be:-
\n" ); document.write( "m=5\r
\n" ); document.write( "\n" ); document.write( "Now we have a point(2,-1) and slope (5)of the line we can easily find required lines by putting these values in the equation of the straight line poin-slope form.
\n" ); document.write( "m=(y2-y1)/(x2-x1)
\n" ); document.write( "5=(y-(-1))/(x-2)
\n" ); document.write( "5=(y+1)/(x-2)
\n" ); document.write( "5(x-2)=y+1
\n" ); document.write( "5x-10=y+1
\n" ); document.write( "y+1=5x-10
\n" ); document.write( "y=5x-10-1
\n" ); document.write( "y=5x-11
\n" ); document.write( "Above equation is the required equation of the line that is parallel to y=5x and contains (2,-1)
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