document.write( "Question 516340: Two buses leave Dallas at the same time and travel in opposite directions. One bus travels at 58 mph and the other travels at 52mph when will they be 363 miles apart? \n" ); document.write( "
Algebra.Com's Answer #344345 by Maths68(1474)\"\" \"About 
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Bus A Data
\n" ); document.write( "==========
\n" ); document.write( "Speed = 58mph
\n" ); document.write( "Time=t hour
\n" ); document.write( "Distance Covered by Bus A=58*t
\n" ); document.write( "=============
\n" ); document.write( "Bus B Data
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\n" ); document.write( "Speed = 52mph
\n" ); document.write( "Time=t hour
\n" ); document.write( "Distance covered by Bus B=52*t\r
\n" ); document.write( "\n" ); document.write( "Distance Covered by Bus A + Distance Covered by Bus B = Total Distnace apart
\n" ); document.write( "52t+58t=363
\n" ); document.write( "110t=363
\n" ); document.write( "110t/110=363/110
\n" ); document.write( "t=3.3 hour\r
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\n" ); document.write( "\n" ); document.write( "They will be 363 miles apart after 3.3 hours or 3 hours 18 minutes.\r
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\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "=============
\n" ); document.write( "Bus A Data
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\n" ); document.write( "Speed = 58mph
\n" ); document.write( "Time=3.3 hours
\n" ); document.write( "Distance Covered by Bus A=58*3.3=191.4 miles\r
\n" ); document.write( "\n" ); document.write( "Bus B Data
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\n" ); document.write( "Speed = 52mph
\n" ); document.write( "Time=3.3 hours
\n" ); document.write( "Distance covered by Bus B=52*3.3 = 171.6 miles\r
\n" ); document.write( "\n" ); document.write( "Total Distance between two Buses = 191.4+171.6 = 363 miles\r
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