document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51636>Question 51636</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. how many of each kind of coin are there?: a jar contains 40 coins consisting of dimes and quarters and having a total value of $4.90. how many of each kind of coin are there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #34434 by </B><A HREF=/tutors/aboutme.mpl?userid=rchill><B>rchill(405)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rchill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=34434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have two equations:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=q%2Bd=40 ALIGN=MIDDLE  ALT=\"q%2Bd=40\"   DISABLED_style= \"max-width:90%; height:auto;\" > represents the number of q quarters and d dimes, and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.25q%2B.10d=4.90 ALIGN=MIDDLE  ALT=\".25q%2B.10d=4.90\"   DISABLED_style= \"max-width:90%; height:auto;\" > represents the total value of the 40 coins.  Solving for d in the first equation yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=40-q ALIGN=MIDDLE  ALT=\"d=40-q\"   DISABLED_style= \"max-width:90%; height:auto;\" > and we substitute that into the second equation for d:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.25q%2B.10%2A%2840-q%29=4.90 ALIGN=MIDDLE  ALT=\".25q%2B.10%2A%2840-q%29=4.90\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Expanding this latest equation produces <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.25q%2B4-.10q=4.90 ALIGN=MIDDLE  ALT=\".25q%2B4-.10q=4.90\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Now combine like terms:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.15q%2B4=4.90 ALIGN=MIDDLE  ALT=\".15q%2B4=4.90\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Subtracting 4 from each side produces: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.15q=.90 ALIGN=MIDDLE  ALT=\".15q=.90\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  And now divide both sides by .15 yields <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=q=6 ALIGN=MIDDLE  ALT=\"q=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  That means there are 6 quarters.  Because we know there are 40 coins total, there must be 40-6, or 34, dimes.  To verify that answer, 34 dimes is $3.40 and 6 quarters is $1.50.  Adding those two values together produces $4.90, which means our answer of 6 quarters and 34 dimes is correct. </SPAN>\n" );
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