document.write( "Question 516311: what is the equation of the line that contains the point (-1,-2) and is perpendicular to the line determined by 2x-3y=6? \n" ); document.write( "

Algebra.Com's Answer #344338 by mananth(16946) $\"\"$ $\"About$

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2 x -3 y = 6
\n" ); document.write( "Find the slope of this line
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\n" ); document.write( "-3 y = -2 x + 6
\n" ); document.write( "Divide by -3
\n" ); document.write( " y = 0.667 x + -2
\n" ); document.write( "Compare this equation with y=mx+b
\n" ); document.write( "slope m = 0.67
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -1.5
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be
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\n" ); document.write( "m= -1 1/2 ,point ( -1 , -2 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "-2 = 1.50 + b
\n" ); document.write( "b= -3.5
\n" ); document.write( "m= -3/2
\n" ); document.write( "The required equation is y=-3/ 2 x-7/ 2
\n" ); document.write( "m.ananth@hotmail.ca
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