document.write( "Question 516265: Two numbers are in ratio of 7:11. If 7 is added to each of the number, the ratio becomes 2:3. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #344313 by Maths68(1474) $\"\"$ $\"About$

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Let x and y are two numbers\r
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\n" ); document.write( "\n" ); document.write( "x:y=7:11
\n" ); document.write( "x/y=7/11
\n" ); document.write( "11x=7y
\n" ); document.write( "x=7y/11............(1)\r
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\n" ); document.write( "\n" ); document.write( "(x+7):(y+7)=2:3
\n" ); document.write( "(x+7)/(y+7)=2/3
\n" ); document.write( "3(x+7)=2(y+7)
\n" ); document.write( "3x+21=2y+14
\n" ); document.write( "3x=2y+14-21
\n" ); document.write( "3x=2y-7............(2)
\n" ); document.write( "Put the value of x in (2) from (1)
\n" ); document.write( "3(7y/11)=2y-7
\n" ); document.write( "21y/11=2y-7
\n" ); document.write( "21y=11*(2y-7)
\n" ); document.write( "21y=22y-77
\n" ); document.write( "21y-22y=-77
\n" ); document.write( "-y=-77
\n" ); document.write( "y=77
\n" ); document.write( "Put the value of y in (1)\r
\n" ); document.write( "\n" ); document.write( "x=7y/11............(1)
\n" ); document.write( "x=7(77)/11
\n" ); document.write( "x=7*7
\n" ); document.write( "x=49\r
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\n" ); document.write( "\n" ); document.write( "Numbers are 49 and 77\r
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\n" ); document.write( "\n" ); document.write( "49/77=7/11=7:11
\n" ); document.write( "(49+7)/(77+7)=56/84=28/42=14/21=2/3=2:3 \n" ); document.write( "

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