document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=516279>Question 516279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the third of the three consecutive positive odd integers is added to product of the first and second,the result is 144 find the integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344310 by </B><A HREF=/tutors/aboutme.mpl?userid=gc2000><B>gc2000(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gc2000><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gc2000><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344310\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let consecutive positive odd integers = x, x+2, x+4<BR>\n" );
document.write( "add 3rd to product of 1st & 2nd, it totals 144:<BR>\n" );
document.write( "(x)(x+2) + (x+4) = 144<BR>\n" );
document.write( "x^2 + 2x + x + 4 = 144<BR>\n" );
document.write( "x^2 + 3x + 4 = 144<BR>\n" );
document.write( "x^2 + 3x - 140 = 0<BR>\n" );
document.write( "(x +   14)(x - 10) [oops, that doesn't factor, did I make a mistake?]\r<BR>\n" );
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document.write( "Check by Trial and error:\r<BR>\n" );
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document.write( "9 11 13 ... 9*11 + 13 = 112\r<BR>\n" );
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document.write( "11 13 15 ... 11*13 + 15 = 158\r<BR>\n" );
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document.write( "No mistake. There is NO SOLUTION [or perhaps the question wasn't worded correctly?]\r<BR>\n" );
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document.write( "  </SPAN>\n" );
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