document.write( "Question 515860: Find the formula.\r
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document.write( "Ellipse with foci at (5, 1) and (-1, 1) and contains a point at (1, 3) \n" );
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Algebra.Com's Answer #344303 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the formula. \n" ); document.write( "Ellipse with foci at (5, 1) and (-1, 1) and contains a point at (1, 3) \n" ); document.write( "** \n" ); document.write( "Gleaned from coordinates of foci, this is an ellipse with a horizontal major axis (x changes, but y does not change) of the standard form: (x-h)^2/a^2+(y-k)^2/b^2=1, a>b, with (h,k) being the (x,y) coordinates of the center. \n" ); document.write( "For given equation: \n" ); document.write( "center: (2,1) \n" ); document.write( "Equation: (x-2)^2/a^2+(y-1)^2/b^2=1 \n" ); document.write( "From foci info, c=3 \n" ); document.write( "c^2=a^2-b^2=9 \n" ); document.write( "b^2=a^2-9 \n" ); document.write( "using (x,y) coordinates of given point (1, 3) to solve for a \n" ); document.write( "(x-2)^2/a^2+(y-1)^2/b^2=1 \n" ); document.write( "(1-2)^2/a^2+(3-1)^2/(a^2-9)=1 \n" ); document.write( "1/a^2+4/(a^2-9)=1 \n" ); document.write( "a^2-9+4a^2=a^4-9a^2 \n" ); document.write( "a^4-9a^2-a^2-4a^2+9 \n" ); document.write( "a^4-14a^2+9=0 \n" ); document.write( "solving a with quadratic formula: (let student do this) \n" ); document.write( "a^2=13.3246 \n" ); document.write( "b^2=a^2-9=4.3246 \n" ); document.write( ".. \n" ); document.write( "equation: \n" ); document.write( "(x-2)^2/13.3246+(y-1)^2/4.3246=1\r \n" ); document.write( "\n" ); document.write( "comment: I was hoping to get an exact answer but this is the closest I could get. The answer itself, however, is not as important as the method to get the answer. \n" ); document.write( "See the graph below as a visual check on the answer. \n" ); document.write( "y=±(4.3256-(4.3256/13.3246)(x-2)^2)^.5+1 \n" ); document.write( " |