document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=6414>Question 6414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x/5-x/3=8/15 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #3443 by </B><A HREF=/tutors/aboutme.mpl?userid=digitalbeachbum><B>digitalbeachbum(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=digitalbeachbum><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=3443\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In order to solve this problem you must remember that to add or subtract fractions you must have like terms on the denominator (or the value under the line).\r<BR>\n" );
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document.write( "Original problem:<BR>\n" );
document.write( "x/5 - x/3 = 8/15\r<BR>\n" );
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document.write( "Step 1:  Find like denominators<BR>\n" );
document.write( "x/15 - x/15 = 8/15\r<BR>\n" );
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document.write( "Step 2: Multiply the numerator (the x in this equation) by the same value used to multiple the denominator.<BR>\n" );
document.write( "3x/15 - 5x/15 = 8/15\r<BR>\n" );
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document.write( "Step 3: Subtract the numerators<BR>\n" );
document.write( "3x/15 - 5x/15 = -2x/15\r<BR>\n" );
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document.write( "Step 4: Solve for X<BR>\n" );
document.write( "-2x/15=8/15 (8 divided by -2 is -4)\r<BR>\n" );
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document.write( "x=-4\r<BR>\n" );
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document.write( "Hope this helps.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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