document.write( "Question 516236: How do I solve 0.3x-0.2y=4 and 0.2x + 0.3y=29/19 using the elimination method? \n" ); document.write( "
Algebra.Com's Answer #344292 by mananth(16949)\"\" \"About 
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0.3x-0.2y=4
\n" ); document.write( "multiply by 10
\n" ); document.write( "3x-2y=40.............1\r
\n" ); document.write( "\n" ); document.write( " and 0.2x + 0.3y=29/19\r
\n" ); document.write( "\n" ); document.write( "multiply by 190\r
\n" ); document.write( "\n" ); document.write( "38x+57y=290.............2\r
\n" ); document.write( "\n" ); document.write( "3 x -2 y = 40 .............1
\n" ); document.write( "38 x + 57 y = 290 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by 57
\n" ); document.write( "Multiply (2) by 2
\n" ); document.write( "171 x -114 y = 2280
\n" ); document.write( "76 x 114 y = 580
\n" ); document.write( "Add the two equations
\n" ); document.write( "247 x = 2860
\n" ); document.write( "/ 247
\n" ); document.write( "x = 11.58
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x + -2 y = 40
\n" ); document.write( "34.74 + -2 y = 40
\n" ); document.write( " -2 y = 40-34.74
\n" ); document.write( " -2 y = 5.26
\n" ); document.write( " y = -2.63
\n" ); document.write( " \n" ); document.write( "
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