document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=321874>Question 321874</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juan drives to work. Because of traffic conditions, he averages 22 miles per hour. He returns home averaging 32 miles per hour. The total travel time is 2and1/4 hours. \r<BR>\n" );
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document.write( "a. Define a variable for the time Juan takes to work. Write an expression for the time Juan takes to return home.\r<BR>\n" );
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document.write( "b. Write and solve an equation to find the time Juan spends driving to work.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344254 by </B><A HREF=/tutors/aboutme.mpl?userid=gc2000><B>gc2000(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gc2000><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gc2000><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Correction:<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "d = (r)(t) <BR>\n" );
document.write( "t = d/r<BR>\n" );
document.write( "let x be variable for d(istance) to work<BR>\n" );
document.write( "Time to work = x/22; Time to return home = x/32\r<BR>\n" );
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document.write( "time + time = 2.25 (= 2 1/4 hrs = 9/4 hrs)<BR>\n" );
document.write( "x/22 + x/32 = 9/4 hrs (NOT 5/2 = 2.5 hrs)<BR>\n" );
document.write( "multiply through by 32*22:<BR>\n" );
document.write( "[(32)(22)(x/22)] + [(32)(22)(x/32)] = (32)(22)(9/4)<BR>\n" );
document.write( "[32x] + [22x] = (4*8)(22)(9/4) = (8)(22)(9)<BR>\n" );
document.write( "54x = 1584<BR>\n" );
document.write( "x = 29.333\r<BR>\n" );
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document.write( "Time to work = x/22 = 29.333/22 = 1.333hrs = 1 hr, 20 min<BR>\n" );
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document.write( "ALSO, please check similar problems/solutions that set distance to work and from work as equal to each other. This alternate method may be easier to set up:<BR>\n" );
document.write( "let x equal <u>time to work</u> (instead of <u>distance to work</u> as I did above)<BR>\n" );
document.write( "then time to work = x<BR>\n" );
document.write( "time to return = difference between total time and time to work<BR>\n" );
document.write( "time to return = 2.25 - x\r<BR>\n" );
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document.write( "Set distances as equal:<BR>\n" );
document.write( "distance to work = distance to return {d = (r)(t)}<BR>\n" );
document.write( "(rate to work)(time to work) = (return rate)(return time)<BR>\n" );
document.write( "(22)(x) = (32)(2.25 - x)<BR>\n" );
document.write( "22x = 72 - 32x<BR>\n" );
document.write( "add 32x to both sides of equation<BR>\n" );
document.write( "54x = 72<BR>\n" );
document.write( "x = 72/54 = 4/3 hrs<BR>\n" );
document.write( "time to work = 1 hour 20 minutes<BR>\n" );
document.write( " </SPAN>\n" );
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