document.write( "Question 516050: Please solve this equation for me: $\"+sqrt%28+y%2B2+%29=y+\"$ \n" ); document.write( "

Algebra.Com's Answer #344241 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+sqrt%28+y%2B2+%29=y+\"$
\n" ); document.write( "square both sides
\n" ); document.write( "y + 2 = y^2
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "0 = y^2 - y - 2
\n" ); document.write( "Factors to:
\n" ); document.write( "(y-2)(y+1) = 0
\n" ); document.write( "two solutions
\n" ); document.write( "y = 2
\n" ); document.write( "y = -1
\n" ); document.write( ":
\n" ); document.write( "Check both solutions in the original problem
\n" ); document.write( "y=2
\n" ); document.write( " $\"+sqrt%28+2%2B2+%29=+2+\"$ ; this works
\n" ); document.write( "y=-1
\n" ); document.write( " $\"+sqrt%28-1%2B2+%29=+-1+\"$ this does not work, only y=2 is a solutions \n" ); document.write( "

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