document.write( "Question 515931: A particular type of bacteria known to be present in cake mix grows continuously at a rate of 10% per day. There are approximately 500 bacteria in the mix when its packaged. how long does it take for the bacteria to reach 4,000,000 \n" ); document.write( "
Algebra.Com's Answer #344228 by ankor@dixie-net.com(22740)\"\" \"About 
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A particular type of bacteria known to be present in cake mix grows continuously at a rate of 10% per day.
\n" ); document.write( " There are approximately 500 bacteria in the mix when its packaged.
\n" ); document.write( " how long does it take for the bacteria to reach 4,000,000
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\n" ); document.write( "A multiplier for a 10% increase = 1.1
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\n" ); document.write( "let t = no. of days for this to happen
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\n" ); document.write( "500*(1.1^t) = 4000000
\n" ); document.write( "divide both sides by 500, results
\n" ); document.write( "1.1^t = 8000
\n" ); document.write( "use logs here
\n" ); document.write( "log(1.1^t) = log(8000)
\n" ); document.write( "the log equiv of exponents
\n" ); document.write( "t*log(1.1) = log(8000)
\n" ); document.write( "divide both sides by log(1.1)
\n" ); document.write( "t = \"log%288000%29%2Flog%281.1%29\"; use a calc on this
\n" ); document.write( "t = 94.3 days
\n" ); document.write( ":
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\n" ); document.write( "Check this: enter into a calc: 500*1.1^94.3 ~ 4000000 \n" ); document.write( "
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