document.write( "Question 515866: jenny invests £3500 at 5% interest per year
\n" );
document.write( "what will she have at the end of 2 years, 5 years,8 years and 9 years? \n" );
document.write( "
Algebra.Com's Answer #344205 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! simple interest \n" ); document.write( "I=Prt \n" ); document.write( "I=3500*0.05*2 \n" ); document.write( "I=350 \n" ); document.write( "3500+350=3850 \n" ); document.write( "--------------- \n" ); document.write( "compounded annually \n" ); document.write( "A=P(1+0.05)^2*1 \n" ); document.write( "A=3500*1.05^2 \n" ); document.write( "A=3858.75 \n" ); document.write( "------- \n" ); document.write( "you do the others. \n" ); document.write( "I gave you both because you did not say which one. \n" ); document.write( " |