document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=515854>Question 515854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the steps that you would take to factor out 2x^2+x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #344178 by </B><A HREF=/tutors/aboutme.mpl?userid=drumwrrv><B>drumwrrv(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drumwrrv><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=344178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^(2)+x+3=0\r<BR>\n" );
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document.write( "Use the quadratic formula to find the solutions.  In this case, the values are a=2, b=1, and c=3.<BR>\n" );
document.write( "x=(-b\~(b^(2)-4ac))/(2a) where ax^(2)+bx+c=0\r<BR>\n" );
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document.write( "Substitute in the values of a=2, b=1, and c=3.<BR>\n" );
document.write( "x=(-1\~((1)^(2)-4(2)(3)))/(2(2))\r<BR>\n" );
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document.write( "Simplify the section inside the radical.<BR>\n" );
document.write( "x=(-1\i~(23))/(2(2))\r<BR>\n" );
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document.write( "Simplify the denominator of the quadratic formula.<BR>\n" );
document.write( "x=(-1\i~(23))/(4)\r<BR>\n" );
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document.write( "First, solve the + portion of \.<BR>\n" );
document.write( "x=(-1+i~(23))/(4)\r<BR>\n" );
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document.write( "Next, solve the - portion of \.<BR>\n" );
document.write( "x=(-1-i~(23))/(4)\r<BR>\n" );
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document.write( "The final answer is the combination of both solutions.<BR>\n" );
document.write( "x=(-1+i~(23))/(4),(-1-i~(23))/(4) </SPAN>\n" );
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