document.write( "Question 515791: The length of a rectangle is 2ft longer than its width.
\n" ); document.write( "If the perimeter of the rectangle is 40ft , find its area.
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Algebra.Com's Answer #344163 by Maths68(1474)\"\" \"About 
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Perimeter = P = 40 ft
\n" ); document.write( "Width = w
\n" ); document.write( "Length = w+2\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 2l +2w
\n" ); document.write( "40=2(w+2)+2w
\n" ); document.write( "40=2w+4+2w
\n" ); document.write( "40=4w+4
\n" ); document.write( "40-4=4w
\n" ); document.write( "36=4w
\n" ); document.write( "36/4=4w/4
\n" ); document.write( "9=w
\n" ); document.write( "w=9\r
\n" ); document.write( "\n" ); document.write( "Perimeter = P = 40 ft
\n" ); document.write( "Width = w = 9
\n" ); document.write( "Length = w+2 = 9+2 = 11
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