document.write( "Question 515696: A solution of 54% fertilizer is to be mixed with a solution of 27% fertilizer to form 135 liters of a 49% solution. How many liters of the 54% solution must be used? \n" ); document.write( "
Algebra.Com's Answer #344128 by mananth(16946)\"\" \"About 
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---------percent ---------------- quantity
\n" ); document.write( "Fertlizer I 54 ---------------- x liters
\n" ); document.write( "Fertilizer II 27 ------ 135 - x liters
\n" ); document.write( "Mixture 49.00% ---------------- 135
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\n" ); document.write( "54 x + 27 ( 135 - x ) = 49 * 135
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\n" ); document.write( "54 x + 3645 - 27 x = 6615
\n" ); document.write( "54 x - 27 x = 6615 - 3645
\n" ); document.write( "27 x = 2970
\n" ); document.write( "/ 27
\n" ); document.write( " x = 110 liters 54.00% Fertlizer I
\n" ); document.write( " 25 liters 27.00% Fertilizer II \r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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